# Equilateral Bimorphic Tilings (2)

With n = 5, the 'FAT' rhombus has angles of 72° and 108° and the 'THIN' rhombus has angles 36° and 144°. As with the case with n = 4, there are a large number of possible vertices but as far as I know, only one of them makes a first order tiling - and it is definitely my all time favourite.

These tilings are of the second order.

Interesting aperiodic results occur if you make arbitrary placement rules. For example, if you stipulate that no two FAT rhombuses shall share a common side (and you deliberately destroy the symmetry of the second tiling above), you get something like this:

Whether this tiling can be extended throughout the plane, I do not know. It certainly appears to be possible.